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(a)speed(b)magnitude of the...
An Earth satellite moves in a circular orbit 640 km above Earth's surface with a period of 98.0 min. What are the(a)speed and(b)magnitude of the centripetal acceleration of the satellite?
最佳解答:
Assume the radius of earth is 6400 km, it means the lenth of orbit is (6400+ 640) *2* 3.1416 = 44237 km. The speed of the satelite will be 44237/(98/60)= 27082 km/hour acceleration equals to V^2/R = 27082*27082/44237 = 16580 km/hour^2
其他解答:CD51EBF2FDB84E83
(a)speed(b)magnitude of the...
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發問:An Earth satellite moves in a circular orbit 640 km above Earth's surface with a period of 98.0 min. What are the(a)speed and(b)magnitude of the centripetal acceleration of the satellite?
最佳解答:
Assume the radius of earth is 6400 km, it means the lenth of orbit is (6400+ 640) *2* 3.1416 = 44237 km. The speed of the satelite will be 44237/(98/60)= 27082 km/hour acceleration equals to V^2/R = 27082*27082/44237 = 16580 km/hour^2
其他解答:CD51EBF2FDB84E83
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